Base | Representation |
---|---|
bin | 1010111011101110100100… |
… | …1110001101100100011010 |
3 | 1120120012220021112110101010 |
4 | 2232323221032031210122 |
5 | 3033423440203424010 |
6 | 41322251042434350 |
7 | 2350335214123536 |
oct | 256735116154432 |
9 | 46505807473333 |
10 | 12021231311130 |
11 | 39151a2756128 |
12 | 14219660629b6 |
13 | 69279c202692 |
14 | 2d7b8b624bc6 |
15 | 15ca76d0e620 |
hex | aeee938d91a |
12021231311130 has 16 divisors (see below), whose sum is σ = 28850955146784. Its totient is φ = 3205661682960.
The previous prime is 12021231311099. The next prime is 12021231311147. The reversal of 12021231311130 is 3111313212021.
It is a junction number, because it is equal to n+sod(n) for n = 12021231311097 and 12021231311106.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 200353855156 + ... + 200353855215.
It is an arithmetic number, because the mean of its divisors is an integer number (1803184696674).
Almost surely, 212021231311130 is an apocalyptic number.
12021231311130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12021231311130 is an abundant number, since it is smaller than the sum of its proper divisors (16829723835654).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12021231311130 is a wasteful number, since it uses less digits than its factorization.
12021231311130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 400707710381.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12021231311130 its reverse (3111313212021), we get a palindrome (15132544523151).
The spelling of 12021231311130 in words is "twelve trillion, twenty-one billion, two hundred thirty-one million, three hundred eleven thousand, one hundred thirty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •