12021437153 has 4 divisors (see below), whose sum is σ = 13114295088. Its totient is φ = 10928579220.

The previous prime is 12021437149. The next prime is 12021437167. The reversal of 12021437153 is 35173412021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35173412021 = 11 ⋅3197582911.

It is a cyclic number.

It is not a de Polignac number, because 12021437153 - 2² = 12021437149 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12021437143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 546428951 + ... + 546428972.

It is an arithmetic number, because the mean of its divisors is an integer number (3278573772).

Almost surely, 2^12021437153 is an apocalyptic number.

It is an amenable number.

12021437153 is a deficient number, since it is larger than the sum of its proper divisors (1092857935).

12021437153 is a wasteful number, since it uses less digits than its factorization.

12021437153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1092857934.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 12021437153 its reverse (35173412021), we get a palindrome (47194849174).

The spelling of 12021437153 in words is "twelve billion, twenty-one million, four hundred thirty-seven thousand, one hundred fifty-three".