Base | Representation |
---|---|
bin | 1010111011101111110001… |
… | …1101100100001101100111 |
3 | 1120120020201202220222202212 |
4 | 2232323330131210031213 |
5 | 3033430120322300033 |
6 | 41322343053154035 |
7 | 2350346213611244 |
oct | 256737435441547 |
9 | 46506652828685 |
10 | 12021554103143 |
11 | 3915348987592 |
12 | 1421a3618b91b |
13 | 692821050680 |
14 | 2d7bbc44c5cb |
15 | 15ca95321748 |
hex | aeefc764367 |
12021554103143 has 16 divisors (see below), whose sum is σ = 13224999029760. Its totient is φ = 10859018237184.
The previous prime is 12021554103127. The next prime is 12021554103157. The reversal of 12021554103143 is 34130145512021.
It is not a de Polignac number, because 12021554103143 - 24 = 12021554103127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12021554103343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22513958 + ... + 23041731.
It is an arithmetic number, because the mean of its divisors is an integer number (826562439360).
Almost surely, 212021554103143 is an apocalyptic number.
12021554103143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12021554103143 is a deficient number, since it is larger than the sum of its proper divisors (1203444926617).
12021554103143 is a wasteful number, since it uses less digits than its factorization.
12021554103143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45556138.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 12021554103143 its reverse (34130145512021), we get a palindrome (46151699615164).
The spelling of 12021554103143 in words is "twelve trillion, twenty-one billion, five hundred fifty-four million, one hundred three thousand, one hundred forty-three".
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