Base | Representation |
---|---|
bin | 1010111011110000101100… |
… | …1000101001001111011101 |
3 | 1120120021100221010220202112 |
4 | 2232330023020221033131 |
5 | 3033431121332330312 |
6 | 41322423325403405 |
7 | 2350355263216202 |
oct | 256741310511735 |
9 | 46507327126675 |
10 | 12021800276957 |
11 | 3915464937619 |
12 | 1421aa4709565 |
13 | 692860053653 |
14 | 2d7c0300dca9 |
15 | 15caabc4bd22 |
hex | aef0b2293dd |
12021800276957 has 2 divisors, whose sum is σ = 12021800276958. Its totient is φ = 12021800276956.
The previous prime is 12021800276947. The next prime is 12021800277083. The reversal of 12021800276957 is 75967200812021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11665852011961 + 355948264996 = 3415531^2 + 596614^2 .
It is a cyclic number.
It is not a de Polignac number, because 12021800276957 - 232 = 12017505309661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12021800276917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010900138478 + 6010900138479.
It is an arithmetic number, because the mean of its divisors is an integer number (6010900138479).
Almost surely, 212021800276957 is an apocalyptic number.
It is an amenable number.
12021800276957 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021800276957 is an equidigital number, since it uses as much as digits as its factorization.
12021800276957 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 846720, while the sum is 50.
The spelling of 12021800276957 in words is "twelve trillion, twenty-one billion, eight hundred million, two hundred seventy-six thousand, nine hundred fifty-seven".
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