12022101121133 has 2 divisors, whose sum is σ = 12022101121134. Its totient is φ = 12022101121132.

The previous prime is 12022101120979. The next prime is 12022101121139. The reversal of 12022101121133 is 33112110122021.

12022101121133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9091027007689 + 2931074113444 = 3015133^2 + 1712038^2 .

It is a cyclic number.

It is not a de Polignac number, because 12022101121133 - 2⁸ = 12022101120877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12022101121139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011050560566 + 6011050560567.

It is an arithmetic number, because the mean of its divisors is an integer number (6011050560567).

Almost surely, 2^{12022101121133} is an apocalyptic number.

It is an amenable number.

12022101121133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022101121133 is an equidigital number, since it uses as much as digits as its factorization.

12022101121133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 12022101121133 its reverse (33112110122021), we get a palindrome (45134211243154).

The spelling of 12022101121133 in words is "twelve trillion, twenty-two billion, one hundred one million, one hundred twenty-one thousand, one hundred thirty-three".