Search a number
-
+
1202211002053 is a prime number
BaseRepresentation
bin10001011111101001010…
…111000001011011000101
311020221010011002122121101
4101133221113001123011
5124144112004031203
62320142122020101
7152566623624115
oct21375127013305
94227104078541
101202211002053
11423944850716
12174bb6047631
13894a269c049
144228a02b045
1521413d7c41d
hex117e95c16c5

1202211002053 has 2 divisors, whose sum is σ = 1202211002054. Its totient is φ = 1202211002052.

The previous prime is 1202211002023. The next prime is 1202211002119. The reversal of 1202211002053 is 3502001122021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 878640020164 + 323570981889 = 937358^2 + 568833^2 .

It is a cyclic number.

It is not a de Polignac number, because 1202211002053 - 237 = 1064772048581 is a prime.

It is a super-2 number, since 2×12022110020532 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1202211002053.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202211002023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601105501026 + 601105501027.

It is an arithmetic number, because the mean of its divisors is an integer number (601105501027).

Almost surely, 21202211002053 is an apocalyptic number.

It is an amenable number.

1202211002053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202211002053 is an equidigital number, since it uses as much as digits as its factorization.

1202211002053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 1202211002053 its reverse (3502001122021), we get a palindrome (4704212124074).

The spelling of 1202211002053 in words is "one trillion, two hundred two billion, two hundred eleven million, two thousand, fifty-three".