120221115145541 has 2 divisors, whose sum is σ = 120221115145542. Its totient is φ = 120221115145540.

The previous prime is 120221115145519. The next prime is 120221115145561. The reversal of 120221115145541 is 145541511122021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95925374222500 + 24295740923041 = 9794150^2 + 4929071^2 .

It is a cyclic number.

It is not a de Polignac number, because 120221115145541 - 2³⁰ = 120220041403717 is a prime.

It is a super-2 number, since 2×120221115145541² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120221115145561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110557572770 + 60110557572771.

It is an arithmetic number, because the mean of its divisors is an integer number (60110557572771).

Almost surely, 2^{120221115145541} is an apocalyptic number.

It is an amenable number.

120221115145541 is a deficient number, since it is larger than the sum of its proper divisors (1).

120221115145541 is an equidigital number, since it uses as much as digits as its factorization.

120221115145541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16000, while the sum is 35.

Adding to 120221115145541 its reverse (145541511122021), we get a palindrome (265762626267562).

The spelling of 120221115145541 in words is "one hundred twenty trillion, two hundred twenty-one billion, one hundred fifteen million, one hundred forty-five thousand, five hundred forty-one".