Base | Representation |
---|---|
bin | 1010111011110001111001… |
… | …0100011000101101111111 |
3 | 1120120022012100202100022102 |
4 | 2232330132110120231333 |
5 | 3033432301230401421 |
6 | 41322515303535315 |
7 | 2350366251651233 |
oct | 256743624305577 |
9 | 46508170670272 |
10 | 12022122122111 |
11 | 391560a581652 |
12 | 1421b7445a53b |
13 | 6928b192c67a |
14 | 2d7c33a6c5c3 |
15 | 15caca12360b |
hex | aef1e518b7f |
12022122122111 has 2 divisors, whose sum is σ = 12022122122112. Its totient is φ = 12022122122110.
The previous prime is 12022122122069. The next prime is 12022122122141. The reversal of 12022122122111 is 11122122122021.
It is a strong prime.
It is an emirp because it is prime and its reverse (11122122122021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12022122122111 - 242 = 7624075611007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022122122141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011061061055 + 6011061061056.
It is an arithmetic number, because the mean of its divisors is an integer number (6011061061056).
Almost surely, 212022122122111 is an apocalyptic number.
12022122122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022122122111 is an equidigital number, since it uses as much as digits as its factorization.
12022122122111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 12022122122111 its reverse (11122122122021), we get a palindrome (23144244244132).
The spelling of 12022122122111 in words is "twelve trillion, twenty-two billion, one hundred twenty-two million, one hundred twenty-two thousand, one hundred eleven".
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