Base | Representation |
---|---|
bin | 10001011111101001011… |
… | …011101011000011001011 |
3 | 11020221010020101120212102 |
4 | 101133221123223003023 |
5 | 124144112312034011 |
6 | 2320142204104015 |
7 | 152566640162225 |
oct | 21375133530313 |
9 | 4227106346772 |
10 | 1202212221131 |
11 | 423945503619 |
12 | 174bb653500b |
13 | 894a2a07bac |
14 | 4228a267415 |
15 | 2141401d73b |
hex | 117e96eb0cb |
1202212221131 has 2 divisors, whose sum is σ = 1202212221132. Its totient is φ = 1202212221130.
The previous prime is 1202212221109. The next prime is 1202212221181. The reversal of 1202212221131 is 1311222122021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1202212221131 - 210 = 1202212220107 is a prime.
It is a super-2 number, since 2×12022122211312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1202212221101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601106110565 + 601106110566.
It is an arithmetic number, because the mean of its divisors is an integer number (601106110566).
Almost surely, 21202212221131 is an apocalyptic number.
1202212221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202212221131 is an equidigital number, since it uses as much as digits as its factorization.
1202212221131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1202212221131 its reverse (1311222122021), we get a palindrome (2513434343152).
The spelling of 1202212221131 in words is "one trillion, two hundred two billion, two hundred twelve million, two hundred twenty-one thousand, one hundred thirty-one".
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