12022130033 has 2 divisors, whose sum is σ = 12022130034. Its totient is φ = 12022130032.

The previous prime is 12022130011. The next prime is 12022130051. The reversal of 12022130033 is 33003122021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6422900449 + 5599229584 = 80143^2 + 74828^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12022130033 is a prime.

It is a super-2 number, since 2×12022130033² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12022129993 and 12022130020.

It is not a weakly prime, because it can be changed into another prime (12022130333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011065016 + 6011065017.

It is an arithmetic number, because the mean of its divisors is an integer number (6011065017).

Almost surely, 2^12022130033 is an apocalyptic number.

It is an amenable number.

12022130033 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022130033 is an equidigital number, since it uses as much as digits as its factorization.

12022130033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 12022130033 its reverse (33003122021), we get a palindrome (45025252054).

The spelling of 12022130033 in words is "twelve billion, twenty-two million, one hundred thirty thousand, thirty-three".