12022130133119 has 4 divisors (see below), whose sum is σ = 12113902119000. Its totient is φ = 11930358147240.

The previous prime is 12022130133089. The next prime is 12022130133121. The reversal of 12022130133119 is 91133103122021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12022130133119 is a prime.

It is a super-2 number, since 2×12022130133119² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12022130133091 and 12022130133100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12022130133179) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45885992744 + ... + 45885993005.

It is an arithmetic number, because the mean of its divisors is an integer number (3028475529750).

Almost surely, 2^{12022130133119} is an apocalyptic number.

12022130133119 is a deficient number, since it is larger than the sum of its proper divisors (91771985881).

12022130133119 is an equidigital number, since it uses as much as digits as its factorization.

12022130133119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91771985880.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 12022130133119 in words is "twelve trillion, twenty-two billion, one hundred thirty million, one hundred thirty-three thousand, one hundred nineteen".