Base | Representation |
---|---|
bin | 1010111011110001111011… |
… | …0011010010100011101111 |
3 | 1120120022012220222221010001 |
4 | 2232330132303102203233 |
5 | 3033432310314121333 |
6 | 41322520153325131 |
7 | 2350366410552052 |
oct | 256743663224357 |
9 | 46508186887101 |
10 | 12022130223343 |
11 | 3915614105189 |
12 | 1421b771067a7 |
13 | 6928b3507bb6 |
14 | 2d7c34b7aa99 |
15 | 15cacabc3b7d |
hex | aef1ecd28ef |
12022130223343 has 2 divisors, whose sum is σ = 12022130223344. Its totient is φ = 12022130223342.
The previous prime is 12022130223331. The next prime is 12022130223401. The reversal of 12022130223343 is 34332203122021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12022130223343 - 233 = 12013540288751 is a prime.
It is a super-2 number, since 2×120221302233432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022130293343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011065111671 + 6011065111672.
It is an arithmetic number, because the mean of its divisors is an integer number (6011065111672).
Almost surely, 212022130223343 is an apocalyptic number.
12022130223343 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022130223343 is an equidigital number, since it uses as much as digits as its factorization.
12022130223343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 12022130223343 its reverse (34332203122021), we get a palindrome (46354333345364).
The spelling of 12022130223343 in words is "twelve trillion, twenty-two billion, one hundred thirty million, two hundred twenty-three thousand, three hundred forty-three".
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