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12022131120330 = 235400737704011
BaseRepresentation
bin1010111011110001111011…
…0110101101100011001010
31120120022012222200111112210
42232330132312231203022
53033432311031322310
641322520224445550
72350366421306142
oct256743666554312
946508188614483
1012022131120330
1139156146680a1
121421b774798b6
136928b3760266
142d7c34d31922
1515cacacee820
hexaef1edad8ca

12022131120330 has 16 divisors (see below), whose sum is σ = 28853114688864. Its totient is φ = 3205901632080.

The previous prime is 12022131120271. The next prime is 12022131120383. The reversal of 12022131120330 is 3302113122021.

It is a junction number, because it is equal to n+sod(n) for n = 12022131120297 and 12022131120306.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 200368851976 + ... + 200368852035.

It is an arithmetic number, because the mean of its divisors is an integer number (1803319668054).

Almost surely, 212022131120330 is an apocalyptic number.

12022131120330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12022131120330 is an abundant number, since it is smaller than the sum of its proper divisors (16830983568534).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12022131120330 is a wasteful number, since it uses less digits than its factorization.

12022131120330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 400737704021.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12022131120330 its reverse (3302113122021), we get a palindrome (15324244242351).

The spelling of 12022131120330 in words is "twelve trillion, twenty-two billion, one hundred thirty-one million, one hundred twenty thousand, three hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 400737704011 801475408022 1202213112033 2003688520055 2404426224066 4007377040110 6011065560165 12022131120330