1202213133113 has 4 divisors (see below), whose sum is σ = 1265487508560. Its totient is φ = 1138938757668.

The previous prime is 1202213133097. The next prime is 1202213133157. The reversal of 1202213133113 is 3113313122021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1202213133113 - 2⁴ = 1202213133097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1202213133193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31637187695 + ... + 31637187732.

It is an arithmetic number, because the mean of its divisors is an integer number (316371877140).

Almost surely, 2^{1202213133113} is an apocalyptic number.

It is an amenable number.

1202213133113 is a deficient number, since it is larger than the sum of its proper divisors (63274375447).

1202213133113 is an equidigital number, since it uses as much as digits as its factorization.

1202213133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63274375446.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1202213133113 its reverse (3113313122021), we get a palindrome (4315526255134).

The spelling of 1202213133113 in words is "one trillion, two hundred two billion, two hundred thirteen million, one hundred thirty-three thousand, one hundred thirteen".