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120221319937 is a prime number
BaseRepresentation
bin110111111110110111…
…1111100001100000001
3102111022102121211101011
41233331233330030001
53432203124214222
6131121240040521
711454124234015
oct1577557741401
9374272554334
10120221319937
1146a9288a064
121b371a63141
13b44bcc7804
145b668b8545
1531d9621c77
hex1bfdbfc301

120221319937 has 2 divisors, whose sum is σ = 120221319938. Its totient is φ = 120221319936.

The previous prime is 120221319913. The next prime is 120221319941. The reversal of 120221319937 is 739913122021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87030310081 + 33191009856 = 295009^2 + 182184^2 .

It is a cyclic number.

It is not a de Polignac number, because 120221319937 - 219 = 120220795649 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120221319937.

It is not a weakly prime, because it can be changed into another prime (120221319037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110659968 + 60110659969.

It is an arithmetic number, because the mean of its divisors is an integer number (60110659969).

Almost surely, 2120221319937 is an apocalyptic number.

It is an amenable number.

120221319937 is a deficient number, since it is larger than the sum of its proper divisors (1).

120221319937 is an equidigital number, since it uses as much as digits as its factorization.

120221319937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40824, while the sum is 40.

The spelling of 120221319937 in words is "one hundred twenty billion, two hundred twenty-one million, three hundred nineteen thousand, nine hundred thirty-seven".