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1202220010331 = 2934103139967
BaseRepresentation
bin10001011111101001111…
…001011000101101011011
311020221010210001022122022
4101133221321120231123
5124144121310312311
62320143043045055
7152600063323244
oct21375171305533
94227123038568
101202220010331
1142394994377a
12174bb907078b
13894a45043a2
144228b2d3ccb
1521414a5b5db
hex117e9e58b5b

1202220010331 has 4 divisors (see below), whose sum is σ = 1206323150592. Its totient is φ = 1198116870072.

The previous prime is 1202220010309. The next prime is 1202220010393. The reversal of 1202220010331 is 1330100222021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1202220010331 is a prime.

It is a super-2 number, since 2×12022200103312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1202220010301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2051569691 + ... + 2051570276.

It is an arithmetic number, because the mean of its divisors is an integer number (301580787648).

Almost surely, 21202220010331 is an apocalyptic number.

1202220010331 is a deficient number, since it is larger than the sum of its proper divisors (4103140261).

1202220010331 is an equidigital number, since it uses as much as digits as its factorization.

1202220010331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4103140260.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1202220010331 its reverse (1330100222021), we get a palindrome (2532320232352).

The spelling of 1202220010331 in words is "one trillion, two hundred two billion, two hundred twenty million, ten thousand, three hundred thirty-one".

Divisors: 1 293 4103139967 1202220010331