Base | Representation |
---|---|
bin | 1010111011110010001100… |
… | …0001010010010000110011 |
3 | 1120120022101212011210211011 |
4 | 2232330203001102100303 |
5 | 3033432431424013021 |
6 | 41322531202331351 |
7 | 2350401230264665 |
oct | 256744301222063 |
9 | 46508355153734 |
10 | 12022201001011 |
11 | 3915650057523 |
12 | 1421b96959b57 |
13 | 6928c5089686 |
14 | 2d7c40322535 |
15 | 15cad2004de1 |
hex | aef23052433 |
12022201001011 has 2 divisors, whose sum is σ = 12022201001012. Its totient is φ = 12022201001010.
The previous prime is 12022201000993. The next prime is 12022201001021. The reversal of 12022201001011 is 11010010222021.
It is a strong prime.
It is an emirp because it is prime and its reverse (11010010222021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12022201001011 - 221 = 12022198903859 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12022201000982 and 12022201001000.
It is not a weakly prime, because it can be changed into another prime (12022201001021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011100500505 + 6011100500506.
It is an arithmetic number, because the mean of its divisors is an integer number (6011100500506).
Almost surely, 212022201001011 is an apocalyptic number.
12022201001011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022201001011 is an equidigital number, since it uses as much as digits as its factorization.
12022201001011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 12022201001011 its reverse (11010010222021), we get a palindrome (23032211223032).
The spelling of 12022201001011 in words is "twelve trillion, twenty-two billion, two hundred one million, one thousand, eleven".
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