120222012119971 has 2 divisors, whose sum is σ = 120222012119972. Its totient is φ = 120222012119970.

The previous prime is 120222012119917. The next prime is 120222012120019. The reversal of 120222012119971 is 179911210222021.

It is a happy number.

Together with previous prime (120222012119917) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120222012119971 - 2¹³ = 120222012111779 is a prime.

It is not a weakly prime, because it can be changed into another prime (120222012110971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111006059985 + 60111006059986.

It is an arithmetic number, because the mean of its divisors is an integer number (60111006059986).

Almost surely, 2^{120222012119971} is an apocalyptic number.

120222012119971 is a deficient number, since it is larger than the sum of its proper divisors (1).

120222012119971 is an equidigital number, since it uses as much as digits as its factorization.

120222012119971 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 40.

The spelling of 120222012119971 in words is "one hundred twenty trillion, two hundred twenty-two billion, twelve million, one hundred nineteen thousand, nine hundred seventy-one".