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120222041 is a prime number
BaseRepresentation
bin1110010101001…
…11000101011001
322101012220122012
413022213011121
5221234101131
615532435305
72656604402
oct712470531
9271186565
10120222041
1161953665
1234318b35
131bba4004
1411d769a9
15a84b52b
hex72a7159

120222041 has 2 divisors, whose sum is σ = 120222042. Its totient is φ = 120222040.

The previous prime is 120222031. The next prime is 120222043. The reversal of 120222041 is 140222021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108076816 + 12145225 = 10396^2 + 3485^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120222041 is a prime.

Together with 120222043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (120222043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111020 + 60111021.

It is an arithmetic number, because the mean of its divisors is an integer number (60111021).

Almost surely, 2120222041 is an apocalyptic number.

It is an amenable number.

120222041 is a deficient number, since it is larger than the sum of its proper divisors (1).

120222041 is an equidigital number, since it uses as much as digits as its factorization.

120222041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 14.

The square root of 120222041 is about 10964.5812049526. The cubic root of 120222041 is about 493.5464497510.

Adding to 120222041 its reverse (140222021), we get a palindrome (260444062).

The spelling of 120222041 in words is "one hundred twenty million, two hundred twenty-two thousand, forty-one".