Base | Representation |
---|---|
bin | 1010111011110010010001… |
… | …0010010110011111001111 |
3 | 1120120022110100011110200012 |
4 | 2232330210102112133033 |
5 | 3033433002344030413 |
6 | 41322533242023435 |
7 | 2350401606024116 |
oct | 256744422263717 |
9 | 46508410143605 |
10 | 12022222251983 |
11 | 3915661051709 |
12 | 1421ba1aa7b7b |
13 | 6928c95ba308 |
14 | 2d7c43094c7d |
15 | 15cad3d017a8 |
hex | aef244967cf |
12022222251983 has 2 divisors, whose sum is σ = 12022222251984. Its totient is φ = 12022222251982.
The previous prime is 12022222251967. The next prime is 12022222251997. The reversal of 12022222251983 is 38915222222021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12022222251983 - 24 = 12022222251967 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12022222251983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022222251943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011111125991 + 6011111125992.
It is an arithmetic number, because the mean of its divisors is an integer number (6011111125992).
Almost surely, 212022222251983 is an apocalyptic number.
12022222251983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022222251983 is an equidigital number, since it uses as much as digits as its factorization.
12022222251983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 138240, while the sum is 41.
The spelling of 12022222251983 in words is "twelve trillion, twenty-two billion, two hundred twenty-two million, two hundred fifty-one thousand, nine hundred eighty-three".
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