1202225040131 has 4 divisors (see below), whose sum is σ = 1227804296352. Its totient is φ = 1176645783912.

The previous prime is 1202225040127. The next prime is 1202225040139. The reversal of 1202225040131 is 1310405222021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1202225040131 - 2² = 1202225040127 is a prime.

It is a super-2 number, since 2×1202225040131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1202225040097 and 1202225040106.

It is not an unprimeable number, because it can be changed into a prime (1202225040139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12789628040 + ... + 12789628133.

It is an arithmetic number, because the mean of its divisors is an integer number (306951074088).

Almost surely, 2^{1202225040131} is an apocalyptic number.

1202225040131 is a deficient number, since it is larger than the sum of its proper divisors (25579256221).

1202225040131 is an equidigital number, since it uses as much as digits as its factorization.

1202225040131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25579256220.

The product of its (nonzero) digits is 960, while the sum is 23.

The spelling of 1202225040131 in words is "one trillion, two hundred two billion, two hundred twenty-five million, forty thousand, one hundred thirty-one".