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12022262017 is a prime number
BaseRepresentation
bin10110011001001010…
…10010100100000001
31011000212000012002121
423030211102210001
5144110144341032
65304542444241
7603631353403
oct131445224401
934025005077
1012022262017
11510a287437
1223b6293681
13119795a70c
14820974b73
154a56bba97
hex2cc952901

12022262017 has 2 divisors, whose sum is σ = 12022262018. Its totient is φ = 12022262016.

The previous prime is 12022261991. The next prime is 12022262041. The reversal of 12022262017 is 71026222021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9446090481 + 2576171536 = 97191^2 + 50756^2 .

It is a cyclic number.

It is not a de Polignac number, because 12022262017 - 215 = 12022229249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12022261982 and 12022262000.

It is not a weakly prime, because it can be changed into another prime (12022263017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011131008 + 6011131009.

It is an arithmetic number, because the mean of its divisors is an integer number (6011131009).

Almost surely, 212022262017 is an apocalyptic number.

It is an amenable number.

12022262017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022262017 is an equidigital number, since it uses as much as digits as its factorization.

12022262017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 12022262017 its reverse (71026222021), we get a palindrome (83048484038).

The spelling of 12022262017 in words is "twelve billion, twenty-two million, two hundred sixty-two thousand, seventeen".