120223225514317 has 2 divisors, whose sum is σ = 120223225514318. Its totient is φ = 120223225514316.

The previous prime is 120223225514267. The next prime is 120223225514351. The reversal of 120223225514317 is 713415522322021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96276403698916 + 23946821815401 = 9812054^2 + 4893549^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120223225514317 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120223225514317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120223225514417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111612757158 + 60111612757159.

It is an arithmetic number, because the mean of its divisors is an integer number (60111612757159).

Almost surely, 2^{120223225514317} is an apocalyptic number.

It is an amenable number.

120223225514317 is a deficient number, since it is larger than the sum of its proper divisors (1).

120223225514317 is an equidigital number, since it uses as much as digits as its factorization.

120223225514317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 40.

Adding to 120223225514317 its reverse (713415522322021), we get a palindrome (833638747836338).

The spelling of 120223225514317 in words is "one hundred twenty trillion, two hundred twenty-three billion, two hundred twenty-five million, five hundred fourteen thousand, three hundred seventeen".