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12022413000 = 23353134367107
BaseRepresentation
bin10110011001001011…
…10111011011001000
31011000212021212012120
423030211313123020
5144110214204000
65304550011240
7603632552523
oct131445673310
934025255176
1012022413000
11510a37a914
1223b6346b20
1311979b1360
148209b3bba
154a56eb6a0
hex2cc9776c8

12022413000 has 512 divisors, whose sum is σ = 42343741440. Its totient is φ = 2820787200.

The previous prime is 12022412977. The next prime is 12022413017. The reversal of 12022413000 is 31422021.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 112358947 + ... + 112359053.

It is an arithmetic number, because the mean of its divisors is an integer number (82702620).

Almost surely, 212022413000 is an apocalyptic number.

12022413000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12022413000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21171870720).

12022413000 is an abundant number, since it is smaller than the sum of its proper divisors (30321328440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12022413000 is a wasteful number, since it uses less digits than its factorization.

12022413000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 254 (or 240 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12022413000 its reverse (31422021), we get a palindrome (12053835021).

The spelling of 12022413000 in words is "twelve billion, twenty-two million, four hundred thirteen thousand".