120231212031133 has 6 divisors (see below), whose sum is σ = 139860797668926. Its totient is φ = 103055324598072.

The previous prime is 120231212031103. The next prime is 120231212031137. The reversal of 120231212031133 is 331130212132021.

It can be written as a sum of positive squares in only one way, i.e., 102021857744569 + 18209354286564 = 10100587^2 + 4267242^2 .

It is a de Polignac number, because none of the positive numbers 2^k-120231212031133 is a prime.

It is a super-3 number, since 3×120231212031133³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120231212031098 and 120231212031107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120231212031137) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1226849102310 + ... + 1226849102407.

It is an arithmetic number, because the mean of its divisors is an integer number (23310132944821).

Almost surely, 2^{120231212031133} is an apocalyptic number.

It is an amenable number.

120231212031133 is a deficient number, since it is larger than the sum of its proper divisors (19629585637793).

120231212031133 is an equidigital number, since it uses as much as digits as its factorization.

120231212031133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2453698204731 (or 2453698204724 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 120231212031133 its reverse (331130212132021), we get a palindrome (451361424163154).

The spelling of 120231212031133 in words is "one hundred twenty trillion, two hundred thirty-one billion, two hundred twelve million, thirty-one thousand, one hundred thirty-three".