Base | Representation |
---|---|
bin | 11011010101100110010110… |
… | …001111011000010100101111 |
3 | 120202201000121202101101112021 |
4 | 123111212112033120110233 |
5 | 111224333143233143434 |
6 | 1103413335041251011 |
7 | 34216304434630204 |
oct | 3325462617302457 |
9 | 522630552341467 |
10 | 120231540131119 |
11 | 35344a00a7977a |
12 | 11599817633a67 |
13 | 5211a29c14611 |
14 | 2199347d47cab |
15 | dd7771a28cb4 |
hex | 6d59963d852f |
120231540131119 has 2 divisors, whose sum is σ = 120231540131120. Its totient is φ = 120231540131118.
The previous prime is 120231540131107. The next prime is 120231540131141. The reversal of 120231540131119 is 911131045132021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120231540131119 is a prime.
It is a super-2 number, since 2×1202315401311192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120231540131189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60115770065559 + 60115770065560.
It is an arithmetic number, because the mean of its divisors is an integer number (60115770065560).
Almost surely, 2120231540131119 is an apocalyptic number.
120231540131119 is a deficient number, since it is larger than the sum of its proper divisors (1).
120231540131119 is an equidigital number, since it uses as much as digits as its factorization.
120231540131119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 34.
The spelling of 120231540131119 in words is "one hundred twenty trillion, two hundred thirty-one billion, five hundred forty million, one hundred thirty-one thousand, one hundred nineteen".
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