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120232021131300 = 223521327332485483
BaseRepresentation
bin11011010101100110110010…
…111010010000000000100100
3120202201001212021110201201210
4123111212302322100000210
5111224340134402200200
61103413454502551420
734216322365232121
oct3325466272200044
9522631767421653
10120232021131300
1135345128539291
1211599930738570
135211aa5776600
142199391b95748
15dd779dd8c650
hex6d59b2e90024

120232021131300 has 216 divisors, whose sum is σ = 381849192316704. Its totient is φ = 29190154705920.

The previous prime is 120232021131251. The next prime is 120232021131349. The reversal of 120232021131300 is 3131120232021.

120232021131300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (120232021131251) and next prime (120232021131349).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 12541642 + ... + 19943841.

Almost surely, 2120232021131300 is an apocalyptic number.

120232021131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

120232021131300 is an abundant number, since it is smaller than the sum of its proper divisors (261617171185404).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120232021131300 is a wasteful number, since it uses less digits than its factorization.

120232021131300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32485599 (or 32485579 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 120232021131300 its reverse (3131120232021), we get a palindrome (123363141363321).

The spelling of 120232021131300 in words is "one hundred twenty trillion, two hundred thirty-two billion, twenty-one million, one hundred thirty-one thousand, three hundred".