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12023401017223 is a prime number
BaseRepresentation
bin1010111011110110101010…
…0010111110111110000111
31120120102111111012221121001
42232331222202332332013
53033442411130022343
641323250231034131
72350443041251351
oct256755242767607
946512444187531
1012023401017223
113916106474462
12142227080b947
13692a5688833b
142d7d158580d1
1515cb5254544d
hexaef6a8bef87

12023401017223 has 2 divisors, whose sum is σ = 12023401017224. Its totient is φ = 12023401017222.

The previous prime is 12023401017197. The next prime is 12023401017301. The reversal of 12023401017223 is 32271010432021.

It is a weak prime.

It is an emirp because it is prime and its reverse (32271010432021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12023401017223 - 213 = 12023401009031 is a prime.

It is a super-2 number, since 2×120234010172232 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12023401017191 and 12023401017200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12023401017623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011700508611 + 6011700508612.

It is an arithmetic number, because the mean of its divisors is an integer number (6011700508612).

Almost surely, 212023401017223 is an apocalyptic number.

12023401017223 is a deficient number, since it is larger than the sum of its proper divisors (1).

12023401017223 is an equidigital number, since it uses as much as digits as its factorization.

12023401017223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 12023401017223 its reverse (32271010432021), we get a palindrome (44294411449244).

The spelling of 12023401017223 in words is "twelve trillion, twenty-three billion, four hundred one million, seventeen thousand, two hundred twenty-three".