1202414000321 has 4 divisors (see below), whose sum is σ = 1273144235652. Its totient is φ = 1131683764992.

The previous prime is 1202414000311. The next prime is 1202414000393. The reversal of 1202414000321 is 1230004142021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 859060191025 + 343353809296 = 926855^2 + 585964^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202414000321 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1202414000293 and 1202414000302.

It is not an unprimeable number, because it can be changed into a prime (1202414000311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35365117640 + ... + 35365117673.

It is an arithmetic number, because the mean of its divisors is an integer number (318286058913).

Almost surely, 2^{1202414000321} is an apocalyptic number.

It is an amenable number.

1202414000321 is a deficient number, since it is larger than the sum of its proper divisors (70730235331).

1202414000321 is an equidigital number, since it uses as much as digits as its factorization.

1202414000321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70730235330.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1202414000321 its reverse (1230004142021), we get a palindrome (2432418142342).

The spelling of 1202414000321 in words is "one trillion, two hundred two billion, four hundred fourteen million, three hundred twenty-one", and thus it is an aban number.