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120252123121127 is a prime number
BaseRepresentation
bin11011010101111001100001…
…000101010000010111100111
3120202202222202012220121201112
4123111321201011100113213
5111230202322004334002
61103431021314215235
734220633466306344
oct3325714105202747
9522688665817645
10120252123121127
1135352703598818
12115a180088451b
13521395a31064a
14219a33b8297cb
15dd8078a52852
hex6d5e611505e7

120252123121127 has 2 divisors, whose sum is σ = 120252123121128. Its totient is φ = 120252123121126.

The previous prime is 120252123121121. The next prime is 120252123121147. The reversal of 120252123121127 is 721121321252021.

It is a weak prime.

It is an emirp because it is prime and its reverse (721121321252021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120252123121127 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120252123121093 and 120252123121102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120252123121121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60126061560563 + 60126061560564.

It is an arithmetic number, because the mean of its divisors is an integer number (60126061560564).

Almost surely, 2120252123121127 is an apocalyptic number.

120252123121127 is a deficient number, since it is larger than the sum of its proper divisors (1).

120252123121127 is an equidigital number, since it uses as much as digits as its factorization.

120252123121127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 32.

Adding to 120252123121127 its reverse (721121321252021), we get a palindrome (841373444373148).

The spelling of 120252123121127 in words is "one hundred twenty trillion, two hundred fifty-two billion, one hundred twenty-three million, one hundred twenty-one thousand, one hundred twenty-seven".