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120254045143 = 432796605701
BaseRepresentation
bin110111111111110110…
…0110001101111010111
3102111101201012102220211
41233333230301233113
53432240013421033
6131124405310251
711455002342541
oct1577754615727
9374351172824
10120254045143
1146aaa300a91
121b380a05387
13b455a1503b
145b6ad96691
1531dc4382cd
hex1bffb31bd7

120254045143 has 4 divisors (see below), whose sum is σ = 123050650888. Its totient is φ = 117457439400.

The previous prime is 120254045117. The next prime is 120254045159. The reversal of 120254045143 is 341540452021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 341540452021 = 2029168329449.

It is a cyclic number.

It is not a de Polignac number, because 120254045143 - 229 = 119717174231 is a prime.

It is a super-2 number, since 2×1202540451432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120254045113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1398302808 + ... + 1398302893.

It is an arithmetic number, because the mean of its divisors is an integer number (30762662722).

Almost surely, 2120254045143 is an apocalyptic number.

120254045143 is a deficient number, since it is larger than the sum of its proper divisors (2796605745).

120254045143 is an equidigital number, since it uses as much as digits as its factorization.

120254045143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2796605744.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 120254045143 its reverse (341540452021), we get a palindrome (461794497164).

The spelling of 120254045143 in words is "one hundred twenty billion, two hundred fifty-four million, forty-five thousand, one hundred forty-three".

Divisors: 1 43 2796605701 120254045143