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1203025740341 is a prime number
BaseRepresentation
bin10001100000011001111…
…011000000001000110101
311021000012221011122102112
4101200121323000020311
5124202244042142331
62320355024420405
7152626046033315
oct21403173001065
94230187148375
101203025740341
11424222738647
121751a2a77705
13895a24123c9
1442326311445
152146066632b
hex11819ec0235

1203025740341 has 2 divisors, whose sum is σ = 1203025740342. Its totient is φ = 1203025740340.

The previous prime is 1203025740337. The next prime is 1203025740347. The reversal of 1203025740341 is 1430475203021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1078127112241 + 124898628100 = 1038329^2 + 353410^2 .

It is an emirp because it is prime and its reverse (1430475203021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1203025740341 - 22 = 1203025740337 is a prime.

It is a super-2 number, since 2×12030257403412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1203025740298 and 1203025740307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1203025740347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601512870170 + 601512870171.

It is an arithmetic number, because the mean of its divisors is an integer number (601512870171).

Almost surely, 21203025740341 is an apocalyptic number.

It is an amenable number.

1203025740341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1203025740341 is an equidigital number, since it uses as much as digits as its factorization.

1203025740341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 32.

The spelling of 1203025740341 in words is "one trillion, two hundred three billion, twenty-five million, seven hundred forty thousand, three hundred forty-one".