Base | Representation |
---|---|
bin | 11011010110110000011110… |
… | …001110110101010010100011 |
3 | 120202222122001120211112202111 |
4 | 123112300132032311102203 |
5 | 111232134144030202243 |
6 | 1103514100504100151 |
7 | 34225122661665202 |
oct | 3326603616652243 |
9 | 522878046745674 |
10 | 120311131100323 |
11 | 35375734001979 |
12 | 115b112a464657 |
13 | 52193a2395477 |
14 | 219d13864b239 |
15 | dd987e14d39d |
hex | 6d6c1e3b54a3 |
120311131100323 has 2 divisors, whose sum is σ = 120311131100324. Its totient is φ = 120311131100322.
The previous prime is 120311131100317. The next prime is 120311131100351. The reversal of 120311131100323 is 323001131113021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120311131100323 - 25 = 120311131100291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120311131100294 and 120311131100303.
It is not a weakly prime, because it can be changed into another prime (120311131400323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60155565550161 + 60155565550162.
It is an arithmetic number, because the mean of its divisors is an integer number (60155565550162).
Almost surely, 2120311131100323 is an apocalyptic number.
120311131100323 is a deficient number, since it is larger than the sum of its proper divisors (1).
120311131100323 is an equidigital number, since it uses as much as digits as its factorization.
120311131100323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 120311131100323 its reverse (323001131113021), we get a palindrome (443312262213344).
The spelling of 120311131100323 in words is "one hundred twenty trillion, three hundred eleven billion, one hundred thirty-one million, one hundred thousand, three hundred twenty-three".
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