Base | Representation |
---|---|
bin | 1010111100010011110000… |
… | …1011010101111000011111 |
3 | 1120121011122220211220110121 |
4 | 2233010330023111320133 |
5 | 3034104411012033041 |
6 | 41331021333015411 |
7 | 2351140450112101 |
oct | 257047413257037 |
9 | 46534586756417 |
10 | 12031213002271 |
11 | 39194550a5451 |
12 | 1423890a84567 |
13 | 69370017c3b8 |
14 | 2d845717d571 |
15 | 15ce5d2a27d1 |
hex | af13c2d5e1f |
12031213002271 has 2 divisors, whose sum is σ = 12031213002272. Its totient is φ = 12031213002270.
The previous prime is 12031213002253. The next prime is 12031213002337. The reversal of 12031213002271 is 17220031213021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12031213002271 - 223 = 12031204613663 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12031213002251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6015606501135 + 6015606501136.
It is an arithmetic number, because the mean of its divisors is an integer number (6015606501136).
Almost surely, 212031213002271 is an apocalyptic number.
12031213002271 is a deficient number, since it is larger than the sum of its proper divisors (1).
12031213002271 is an equidigital number, since it uses as much as digits as its factorization.
12031213002271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 12031213002271 its reverse (17220031213021), we get a palindrome (29251244215292).
The spelling of 12031213002271 in words is "twelve trillion, thirty-one billion, two hundred thirteen million, two thousand, two hundred seventy-one".
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