Base | Representation |
---|---|
bin | 1010111100010100001000… |
… | …1001001110010100011111 |
3 | 1120121011220220012220212111 |
4 | 2233011002021032110133 |
5 | 3034110112124012203 |
6 | 41331035310414451 |
7 | 2351143104034204 |
oct | 257050211162437 |
9 | 46534826186774 |
10 | 12031313110303 |
11 | 39194a6660063 |
12 | 14238ba501427 |
13 | 693717b30116 |
14 | 2d846659bcab |
15 | 15ce66e7926d |
hex | af14224e51f |
12031313110303 has 4 divisors (see below), whose sum is σ = 12031321435408. Its totient is φ = 12031304785200.
The previous prime is 12031313110249. The next prime is 12031313110339. The reversal of 12031313110303 is 30301131313021.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12031313110303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12031313110363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1370526 + ... + 5093227.
It is an arithmetic number, because the mean of its divisors is an integer number (3007830358852).
Almost surely, 212031313110303 is an apocalyptic number.
12031313110303 is a deficient number, since it is larger than the sum of its proper divisors (8325105).
12031313110303 is an equidigital number, since it uses as much as digits as its factorization.
12031313110303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8325104.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 12031313110303 its reverse (30301131313021), we get a palindrome (42332444423324).
The spelling of 12031313110303 in words is "twelve trillion, thirty-one billion, three hundred thirteen million, one hundred ten thousand, three hundred three".
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