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1203132414301 is a prime number
BaseRepresentation
bin10001100000100000010…
…001111011100101011101
311021000111100220020120221
4101200200101323211131
5124203003344224201
62320413355041341
7152631512533156
oct21404021734535
94230440806527
101203132414301
11424277978344
12175212740251
13895bb5518ac
144233655c92d
1521469bd84a1
hex1182047b95d

1203132414301 has 2 divisors, whose sum is σ = 1203132414302. Its totient is φ = 1203132414300.

The previous prime is 1203132414257. The next prime is 1203132414307. The reversal of 1203132414301 is 1034142313021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1128160498201 + 74971916100 = 1062149^2 + 273810^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1203132414301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1203132414307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601566207150 + 601566207151.

It is an arithmetic number, because the mean of its divisors is an integer number (601566207151).

Almost surely, 21203132414301 is an apocalyptic number.

It is an amenable number.

1203132414301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1203132414301 is an equidigital number, since it uses as much as digits as its factorization.

1203132414301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1203132414301 its reverse (1034142313021), we get a palindrome (2237274727322).

The spelling of 1203132414301 in words is "one trillion, two hundred three billion, one hundred thirty-two million, four hundred fourteen thousand, three hundred one".