12031430001 has 4 divisors (see below), whose sum is σ = 16041906672. Its totient is φ = 8020953332.

The previous prime is 12031429999. The next prime is 12031430003. The reversal of 12031430001 is 10003413021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12031429999) and next prime (12031430003).

It is a cyclic number.

It is not a de Polignac number, because 12031430001 - 2¹ = 12031429999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12031430003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2005238331 + ... + 2005238336.

It is an arithmetic number, because the mean of its divisors is an integer number (4010476668).

Almost surely, 2^12031430001 is an apocalyptic number.

It is an amenable number.

12031430001 is a deficient number, since it is larger than the sum of its proper divisors (4010476671).

12031430001 is an equidigital number, since it uses as much as digits as its factorization.

12031430001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4010476670.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12031430001 its reverse (10003413021), we get a palindrome (22034843022).

The spelling of 12031430001 in words is "twelve billion, thirty-one million, four hundred thirty thousand, one".