Base | Representation |
---|---|
bin | 1010111100010110101100… |
… | …0101100000110000011111 |
3 | 1120121020200202201200122120 |
4 | 2233011223011200300133 |
5 | 3034113014000044403 |
6 | 41331231405114023 |
7 | 2351166114365133 |
oct | 257055305406037 |
9 | 46536622650576 |
10 | 12032000003103 |
11 | 3919819367863 |
12 | 1423a70558913 |
13 | 6937c7230572 |
14 | 2d84cd8c33c3 |
15 | 15cea740ce53 |
hex | af16b160c1f |
12032000003103 has 4 divisors (see below), whose sum is σ = 16042666670808. Its totient is φ = 8021333335400.
The previous prime is 12032000003087. The next prime is 12032000003171. The reversal of 12032000003103 is 30130000023021.
12032000003103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12032000003103 - 24 = 12032000003087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12032000003503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2005333333848 + ... + 2005333333853.
It is an arithmetic number, because the mean of its divisors is an integer number (4010666667702).
Almost surely, 212032000003103 is an apocalyptic number.
12032000003103 is a deficient number, since it is larger than the sum of its proper divisors (4010666667705).
12032000003103 is an equidigital number, since it uses as much as digits as its factorization.
12032000003103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4010666667704.
The product of its (nonzero) digits is 108, while the sum is 15.
Adding to 12032000003103 its reverse (30130000023021), we get a palindrome (42162000026124).
The spelling of 12032000003103 in words is "twelve trillion, thirty-two billion, three thousand, one hundred three".
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