120325035155541 has 4 divisors (see below), whose sum is σ = 160433380207392. Its totient is φ = 80216690103692.

The previous prime is 120325035155537. The next prime is 120325035155551. The reversal of 120325035155541 is 145551530523021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120325035155541 - 2² = 120325035155537 is a prime.

It is a super-2 number, since 2×120325035155541² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120325035155493 and 120325035155502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120325035155551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20054172525921 + ... + 20054172525926.

It is an arithmetic number, because the mean of its divisors is an integer number (40108345051848).

Almost surely, 2^{120325035155541} is an apocalyptic number.

It is an amenable number.

120325035155541 is a deficient number, since it is larger than the sum of its proper divisors (40108345051851).

120325035155541 is an equidigital number, since it uses as much as digits as its factorization.

120325035155541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40108345051850.

The product of its (nonzero) digits is 450000, while the sum is 42.

Adding to 120325035155541 its reverse (145551530523021), we get a palindrome (265876565678562).

The spelling of 120325035155541 in words is "one hundred twenty trillion, three hundred twenty-five billion, thirty-five million, one hundred fifty-five thousand, five hundred forty-one".