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12034051153 = 15179695703
BaseRepresentation
bin10110011010100100…
…10000110001010001
31011001200012010202021
423031102100301101
5144121204114103
65310043251441
7604133514145
oct131522206121
934050163667
1012034051153
1151159a9823
1223ba219b81
13119a227737
14822363225
154a6749bbd
hex2cd490c51

12034051153 has 4 divisors (see below), whose sum is σ = 12113747008. Its totient is φ = 11954355300.

The previous prime is 12034051123. The next prime is 12034051291. The reversal of 12034051153 is 35115043021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35115043021 = 191848160159.

It is a cyclic number.

It is not a de Polignac number, because 12034051153 - 229 = 11497180241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12034051123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39847701 + ... + 39848002.

It is an arithmetic number, because the mean of its divisors is an integer number (3028436752).

Almost surely, 212034051153 is an apocalyptic number.

It is an amenable number.

12034051153 is a deficient number, since it is larger than the sum of its proper divisors (79695855).

12034051153 is an equidigital number, since it uses as much as digits as its factorization.

12034051153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79695854.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 12034051153 its reverse (35115043021), we get a palindrome (47149094174).

The spelling of 12034051153 in words is "twelve billion, thirty-four million, fifty-one thousand, one hundred fifty-three".

Divisors: 1 151 79695703 12034051153