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1203424340113 = 1487809296799
BaseRepresentation
bin10001100000110001101…
…011100010100010010001
311021001020201012121112001
4101200301223202202101
5124204103112340423
62320502344034001
7152641656053632
oct21406153424221
94231221177461
101203424340113
11424407737546
12175294462901
1389636b83568
144236322d889
152148564ecad
hex11831ae2891

1203424340113 has 4 divisors (see below), whose sum is σ = 1204233638400. Its totient is φ = 1202615041828.

The previous prime is 1203424340087. The next prime is 1203424340119. The reversal of 1203424340113 is 3110434243021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1203424340113 - 25 = 1203424340081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1203424340119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 404646913 + ... + 404649886.

It is an arithmetic number, because the mean of its divisors is an integer number (301058409600).

Almost surely, 21203424340113 is an apocalyptic number.

It is an amenable number.

1203424340113 is a deficient number, since it is larger than the sum of its proper divisors (809298287).

1203424340113 is an equidigital number, since it uses as much as digits as its factorization.

1203424340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 809298286.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 1203424340113 its reverse (3110434243021), we get a palindrome (4313858583134).

The spelling of 1203424340113 in words is "one trillion, two hundred three billion, four hundred twenty-four million, three hundred forty thousand, one hundred thirteen".

Divisors: 1 1487 809296799 1203424340113