12034403401333 has 4 divisors (see below), whose sum is σ = 12034492220268. Its totient is φ = 12034314582400.

The previous prime is 12034403401331. The next prime is 12034403401379. The reversal of 12034403401333 is 33310430443021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6316460748049 + 5717942653284 = 2513257^2 + 2391222^2 .

It is a cyclic number.

It is not a de Polignac number, because 12034403401333 - 2¹ = 12034403401331 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12034403401295 and 12034403401304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12034403401331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44205916 + ... + 44477317.

It is an arithmetic number, because the mean of its divisors is an integer number (3008623055067).

Almost surely, 2^{12034403401333} is an apocalyptic number.

It is an amenable number.

12034403401333 is a deficient number, since it is larger than the sum of its proper divisors (88818935).

12034403401333 is an equidigital number, since it uses as much as digits as its factorization.

12034403401333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 88818934.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 12034403401333 its reverse (33310430443021), we get a palindrome (45344833844354).

The spelling of 12034403401333 in words is "twelve trillion, thirty-four billion, four hundred three million, four hundred one thousand, three hundred thirty-three".