Base | Representation |
---|---|
bin | 10110011010110111… |
… | …10001101010000001 |
3 | 1011001211212211212122 |
4 | 23031123301222001 |
5 | 144122323421103 |
6 | 5310212534025 |
7 | 604163642243 |
oct | 131533615201 |
9 | 34054784778 |
10 | 12036545153 |
11 | 5117352586 |
12 | 23bb021315 |
13 | 119a8bb989 |
14 | 822812093 |
15 | 4a6a8db38 |
hex | 2cd6f1a81 |
12036545153 has 2 divisors, whose sum is σ = 12036545154. Its totient is φ = 12036545152.
The previous prime is 12036545089. The next prime is 12036545159. The reversal of 12036545153 is 35154563021.
12036545153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10062697969 + 1973847184 = 100313^2 + 44428^2 .
It is a cyclic number.
It is not a de Polignac number, because 12036545153 - 26 = 12036545089 is a prime.
It is not a weakly prime, because it can be changed into another prime (12036545159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6018272576 + 6018272577.
It is an arithmetic number, because the mean of its divisors is an integer number (6018272577).
Almost surely, 212036545153 is an apocalyptic number.
It is an amenable number.
12036545153 is a deficient number, since it is larger than the sum of its proper divisors (1).
12036545153 is an equidigital number, since it uses as much as digits as its factorization.
12036545153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 35.
The spelling of 12036545153 in words is "twelve billion, thirty-six million, five hundred forty-five thousand, one hundred fifty-three".
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