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12040011331 = 67811775551
BaseRepresentation
bin10110011011010001…
…11111111001000011
31011002002101221120121
423031220333321003
5144124220330311
65310415121111
7604235256565
oct131550777103
934062357517
1012040011331
1151192aa797
122400213197
13119b53357a
14823075335
154a7025b71
hex2cda3fe43

12040011331 has 4 divisors (see below), whose sum is σ = 12041793664. Its totient is φ = 12038229000.

The previous prime is 12040011311. The next prime is 12040011341. The reversal of 12040011331 is 13311004021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12040011331 - 223 = 12031622723 is a prime.

It is a super-3 number, since 3×120400113313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12040011311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 880995 + ... + 894556.

It is an arithmetic number, because the mean of its divisors is an integer number (3010448416).

Almost surely, 212040011331 is an apocalyptic number.

12040011331 is a deficient number, since it is larger than the sum of its proper divisors (1782333).

12040011331 is an equidigital number, since it uses as much as digits as its factorization.

12040011331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1782332.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12040011331 its reverse (13311004021), we get a palindrome (25351015352).

The spelling of 12040011331 in words is "twelve billion, forty million, eleven thousand, three hundred thirty-one".

Divisors: 1 6781 1775551 12040011331