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1204014431341 = 4917124486271
BaseRepresentation
bin10001100001010100110…
…110100011110001101101
311021002202211120100111201
4101201110312203301231
5124211310143300331
62321041103445501
7152662412543341
oct21412466436155
94232684510451
101204014431341
1142468a837847
12175419bb6891
13896cc1bcc77
14423bb757621
15214bc361a61
hex11854da3c6d

1204014431341 has 4 divisors (see below), whose sum is σ = 1204038966784. Its totient is φ = 1203989895900.

The previous prime is 1204014431329. The next prime is 1204014431387. The reversal of 1204014431341 is 1431344104021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1204014431341 - 25 = 1204014431309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1204014431141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12193965 + ... + 12292306.

It is an arithmetic number, because the mean of its divisors is an integer number (301009741696).

Almost surely, 21204014431341 is an apocalyptic number.

It is an amenable number.

1204014431341 is a deficient number, since it is larger than the sum of its proper divisors (24535443).

1204014431341 is an equidigital number, since it uses as much as digits as its factorization.

1204014431341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24535442.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1204014431341 its reverse (1431344104021), we get a palindrome (2635358535362).

The spelling of 1204014431341 in words is "one trillion, two hundred four billion, fourteen million, four hundred thirty-one thousand, three hundred forty-one".

Divisors: 1 49171 24486271 1204014431341