Base | Representation |
---|---|
bin | 111000000100010010… |
… | …1011111101001100111 |
3 | 102111210002201210020121 |
4 | 1300020211133221213 |
5 | 3433041200142413 |
6 | 131151252542411 |
7 | 11461462504252 |
oct | 1601045375147 |
9 | 374702653217 |
10 | 120403130983 |
11 | 47076479423 |
12 | 1b402921a07 |
13 | b47a883b05 |
14 | 5b82ac4099 |
15 | 31ea586b8d |
hex | 1c0895fa67 |
120403130983 has 2 divisors, whose sum is σ = 120403130984. Its totient is φ = 120403130982.
The previous prime is 120403130899. The next prime is 120403131031. The reversal of 120403130983 is 389031304021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120403130983 - 217 = 120402999911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120403530983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60201565491 + 60201565492.
It is an arithmetic number, because the mean of its divisors is an integer number (60201565492).
Almost surely, 2120403130983 is an apocalyptic number.
120403130983 is a deficient number, since it is larger than the sum of its proper divisors (1).
120403130983 is an equidigital number, since it uses as much as digits as its factorization.
120403130983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 120403130983 in words is "one hundred twenty billion, four hundred three million, one hundred thirty thousand, nine hundred eighty-three".
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