12040423143341 has 2 divisors, whose sum is σ = 12040423143342. Its totient is φ = 12040423143340.

The previous prime is 12040423143337. The next prime is 12040423143403. The reversal of 12040423143341 is 14334132404021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8240223795241 + 3800199348100 = 2870579^2 + 1949410^2 .

It is a cyclic number.

It is not a de Polignac number, because 12040423143341 - 2² = 12040423143337 is a prime.

It is a super-4 number, since 4×12040423143341⁴ (a number of 53 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12040423143298 and 12040423143307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12040423143241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020211571670 + 6020211571671.

It is an arithmetic number, because the mean of its divisors is an integer number (6020211571671).

Almost surely, 2^{12040423143341} is an apocalyptic number.

It is an amenable number.

12040423143341 is a deficient number, since it is larger than the sum of its proper divisors (1).

12040423143341 is an equidigital number, since it uses as much as digits as its factorization.

12040423143341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 12040423143341 its reverse (14334132404021), we get a palindrome (26374555547362).

The spelling of 12040423143341 in words is "twelve trillion, forty billion, four hundred twenty-three million, one hundred forty-three thousand, three hundred forty-one".