Base | Representation |
---|---|
bin | 10110011011010101… |
… | …00110110110011011 |
3 | 1011002010012101001212 |
4 | 23031222212312123 |
5 | 144124322324201 |
6 | 5310432133335 |
7 | 604241664233 |
oct | 131552466633 |
9 | 34063171055 |
10 | 12040433051 |
11 | 5119568619 |
12 | 240039724b |
13 | 119b6504ca |
14 | 823144cc3 |
15 | 4a70aaabb |
hex | 2cdaa6d9b |
12040433051 has 2 divisors, whose sum is σ = 12040433052. Its totient is φ = 12040433050.
The previous prime is 12040433029. The next prime is 12040433087. The reversal of 12040433051 is 15033404021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12040433051 - 214 = 12040416667 is a prime.
It is a super-2 number, since 2×120404330512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12040433851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020216525 + 6020216526.
It is an arithmetic number, because the mean of its divisors is an integer number (6020216526).
Almost surely, 212040433051 is an apocalyptic number.
12040433051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12040433051 is an equidigital number, since it uses as much as digits as its factorization.
12040433051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 12040433051 its reverse (15033404021), we get a palindrome (27073837072).
The spelling of 12040433051 in words is "twelve billion, forty million, four hundred thirty-three thousand, fifty-one".
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