Base | Representation |
---|---|
bin | 1010111100111000010001… |
… | …0111001100011011111101 |
3 | 1120122002221222011100112101 |
4 | 2233032010113030123331 |
5 | 3034234444041102303 |
6 | 41335322050305101 |
7 | 2351635360206421 |
oct | 257160427143375 |
9 | 46562858140471 |
10 | 12041014003453 |
11 | 3922624550726 |
12 | 1425767288191 |
13 | 694602873196 |
14 | 2d8b06b00b81 |
15 | 15d333952d1d |
hex | af3845cc6fd |
12041014003453 has 4 divisors (see below), whose sum is σ = 12429433810048. Its totient is φ = 11652594196860.
The previous prime is 12041014003393. The next prime is 12041014003463. The reversal of 12041014003453 is 35430041014021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12041014003453 - 225 = 12040980449021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12041014003463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 194209903251 + ... + 194209903312.
It is an arithmetic number, because the mean of its divisors is an integer number (3107358452512).
Almost surely, 212041014003453 is an apocalyptic number.
It is an amenable number.
12041014003453 is a deficient number, since it is larger than the sum of its proper divisors (388419806595).
12041014003453 is an equidigital number, since it uses as much as digits as its factorization.
12041014003453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 388419806594.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 12041014003453 its reverse (35430041014021), we get a palindrome (47471055017474).
The spelling of 12041014003453 in words is "twelve trillion, forty-one billion, fourteen million, three thousand, four hundred fifty-three".
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