Base | Representation |
---|---|
bin | 10110011011011100… |
… | …10011111001101101 |
3 | 1011002012000200222102 |
4 | 23031232103321231 |
5 | 144130044412023 |
6 | 5310505024445 |
7 | 604253150102 |
oct | 131556237155 |
9 | 34065020872 |
10 | 12041404013 |
11 | 511a071071 |
12 | 2400785125 |
13 | 119b900442 |
14 | 823318aa9 |
15 | 4a71ed628 |
hex | 2cdb93e6d |
12041404013 has 2 divisors, whose sum is σ = 12041404014. Its totient is φ = 12041404012.
The previous prime is 12041404009. The next prime is 12041404117. The reversal of 12041404013 is 31040414021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6071214724 + 5970189289 = 77918^2 + 77267^2 .
It is a cyclic number.
It is not a de Polignac number, because 12041404013 - 22 = 12041404009 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12041404003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020702006 + 6020702007.
It is an arithmetic number, because the mean of its divisors is an integer number (6020702007).
Almost surely, 212041404013 is an apocalyptic number.
It is an amenable number.
12041404013 is a deficient number, since it is larger than the sum of its proper divisors (1).
12041404013 is an equidigital number, since it uses as much as digits as its factorization.
12041404013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 12041404013 its reverse (31040414021), we get a palindrome (43081818034).
The spelling of 12041404013 in words is "twelve billion, forty-one million, four hundred four thousand, thirteen".
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